iOS 13 Jailbreak / iOS 12.4/ iOS 12.3.2 Jailbreak Achieved With Cydia By Sparkey

jailbreak iOS 13

Download Links iOS 12.4 jailbreak/ Cydia

I got a piece of awesome news for you for upcoming jailbreaks like iOS 12.1.3, iOS 12.2, 12.1.4 and so on. Actually, the iOS 12.4 jailbreak and iOS 13 jailbreak has been achieved by Sparkey with Cydia.

Sparkey is a jailbreak developer who is behind the meridian jailbreak has successfully achieve. The jailbreak on iOS 12.4 and iOS 13 with Install Cydia support.

He posted a tweet stating Beta Firmware Alpha Exploits, below tweet is of a jailbroken device on iOS 12.4.

sparkey@iBSparkes

Beta Firmwares Alpha Exploits @qwertyoruiopz

Pwn20wnd Says He’s DONE Implementing Substitute Support Unc0ver IOS 13

You can currently jailbreak iOS 12 to iOS 12.1.2 using unc0ver jailbreakchimera jailbreakor rootlessjb jailbreak. They don’t support iOS 12.1.3, iOS 12.1.4, iOS 12.2, iOS 12.3, iOS 12.3.1, and iOS 12.3.1 currently. As Apple has patched the exploits that were used by the jailbreak tools.

View image on Twitter
iOS 13 Jailbreak

After that he posted a picture of Cydia which is clearly stating the device is jailbroken for iOS 13, he has achieved that even the iOS 13 version is still in beta stage.

ya’ll talk that life me and @qwertyoruiopz really iOS 13 Jailbreak live it

He managed to successfully install Cydia and also the TFP0Of course because without TFP0 you cannot achieve the jailbreak with Cydia.

This means that iOS 12.4 hasn’t even released yet and its got jailbroken in beta stage.

Sparkey is a jailbreak developer and has released jailbreaks in the past. In case you don’t know, a few months ago he posted 2 exploits. That we are using currently in available jailbreaks e.g. Unc0ver jailbreak and Chimera jailbreak.

IOS 13 Betas Are Compatible With Chimera | Apple A9 – A11 Devices Only Support On 12.3 – 12.2

it is not confirmed if he’d release that iOS 12.4 jailbreak and iOS 13 jailbreak or not, but as he released the exploits so there is a chance we might get his jailbreak.